4c^2+400c+2333.33=0

Solution for 4c^2+400c+2333.33=0 equation:

4c^2+400c+2333.33=0

a = 4; b = 400; c = +2333.33;
Δ = b2-4ac
Δ = 4002-4·4·2333.33
Δ = 122666.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-\sqrt{122666.72}}{2*4}=\frac{-400-\sqrt{122666.72}}{8}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+\sqrt{122666.72}}{2*4}=\frac{-400+\sqrt{122666.72}}{8}
$